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Q4. (5 points). Find the equation of the plane that passes through the line of intersection of the two planes x - 2y = 3 and

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and y=z the planes Given planes are x-2y = 3 intersection :- line passing through both y = Z = (from plane 1 24 = x-3 y = x-2Hence the point on the plane is (20, +3, c,,G) Putting this point on the equation of plane x-3y + zad -s + 12 - 4 d d=3 HenceQ6: Giren equation of surface x² + 2y² - 12y-Z = 0 x ² + 2 (y 2 - 64) 2 ( 4² – 64 +9) 2 (y - 3)2 2 + - 18 - Z 1 + Z + 18 >> Z

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