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(a) Find symmetric equations for the line that passes through the point (2, -2, 8) and is parallel to the vector (-1, 3,-4).
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we Know that let @ The point through thorough lines passes (2,-2,8) and vector is (-1, 3,-4). Now option c es Goreet X-2 y* 2-8 o 72 + S Yt2 3 = -4 2 YtQ = and 2-8 = 2 3 -u ad y +2 = 6 = and y = 6-2 .= 4 20 2-8 - -8 and 2 = = -878 Ans co, 4, 0) a)2 - 8 فى ہا 3 = 2 - 8 3 - 2 8 - في - مع اني) प اے ہا 16 4 - 4 ره (9) يA Aus 49 3 ہا رہ

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