Question

You throw a frisbee of mass m = 0.5 kg, and radius r = 0.1 meters, off of a hill, with initial translational speed of v₀ = 5 m/s, from a height of h₀ = 3 meters. The tangential speed of the edge of the frisbee is equal to the initial translational speed, and doesn't change as it travels through the air. Treat the frisbee as a solid disk, and ignore air resistance.

a) What is the initial total Kinetic Energy of the frisbee, in Joules?

b) What is the total Kinetic Energy of the frisbee, when it lands on the ground, in Joules?

vo 애 7

Answer 1

a) using Vore wo 5=0.1 Wo I mv²t1Iwa Initial total benetre 2 (6) Total kinetic energy of frisbee m = 0.5kg e = 0.1m Vo = 5 m/s cho - 3m So redljec energy =1X0.5(5) + -> 6.25 +3.125 (9.375 Joules cachon it lands on ground= 9.375 +ugh -) 9.375+ (o.5x9.8+3) - (24.075 Joules ${*05601)7650) K0.540.1) (50)

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