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A wire 15 meters long is in a magnetic field and has a current of 25 A flowing through it. It has a force of 0.7 N on it due

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\! \! \! \! \! \! \! \! \! $Force on a current carrying conductor in a magnetic field is given by, $\\\\ F = ILB\\\\ $Given, $F = 0.7$N, $I = 25$A, $L = 15$m $\\\\ $Strength of the magnetic field is, $\\\\ B = \frac{F}{IL} = \frac{0.7}{25\times 15} = 1.9\times 10^{-3}$T $=1.9$mT$

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