Question

1.) State the null and hypothesis

Question 1 of 10 (5 points) | Attempt 1 of 1 | View question in a popup 2h 59m Remaining 11.1 Section Exercise 12 (p-value, table) ol. Recovering from surgery: A new postsurgical treatment was compared with a standard treatment. Eight subjects received the new treatment, while eight others (the controls) received the standard treatment. The recovery times, in days, are given below. Treatment 17 18 19 20 21 22 30 32 Control 11 13 14 18 21 23 25 26 Can you conclude that the mean recovery time for those receiving the new treatment is greater than the mean for those receiving the standard treatment? Let u, denote the mean recovery time for the new treatment and u, denote the mean recovery time for the standard treatment. Use the a = 0.01 level and the P-value method. Part: 0 / 5 Part 1 of 5 State the null and alternate hypotheses. H: D<O D> D=0 H: D#0 H2 This is a (Choose one) V test. Х 5 Next Part Submit Assignment © 2020 McGraw-Hill Education. All Rights Reserved. Terms of Use | Privacy

2.) Critical values

3.) P-values

4.)

5.) Reject?

6.) Is there enough evidence?

Answer 1

for Right tailed test = 2.6244 critical Value In excel critical value TINU (1-d, d.f) T. INVco.gg 14) 2. 6244 croitical value x tet P value excel for Right tailed P value=t-T. DIST (t , d. f, TRUE) = 1 - T. D ST (1.2364. 14. TRUE) Palue o 11.83 Here P value > L = 0.01 It is concluded that Null hypothesis is not rejected Also t = 1.2364 < t = 2.62 44 It is concluded that Null hypothesis is not rejected

Date. Conclusion There is enough evidence to clam that the Mean recovery time for those receiving treatment is greater than for those receiving the standard treatment the new mean