Question

Question 1 5 pts data = 63.7 67.7 67.9 76 -901 80.3 84.8 93.9 84.8 76 80.3 85.8 89.3 93.9 98.5 95.9 183 -901 98.5 97.3 96.2 94 92 -901 88.7 85.9 87 85 88.9 84 82.5 83 81.3 77 79.3 72 -901 67 64 -981 62 -901 85 -901 67.7 72 98.5 97.3 103 84.8 62 -901 85.9 94 -901 98.5 89.3 93.9 93.9 96.2 81.3 67 95.9 88.3 84 82.5 79.3 76 67.9 64 -901 76 92 83 -901 63.7 85.8 87 84.8 88.9 88.7 77 80.3 62 98.5 97.3 88.9 82.5 83 76 93.9 85.9 98.5 85 84.8 84.8 95.9 67 88.3 94 67.9 -981 85.8 72 80.3 67.7 63.7 -901 77 89.3 96.2 -901 87 93.9 88.7 -901 92 103 84 76 -901 64 79.3 -901 -901 81.3" This data has invalid values, marked with -901. Run the code above to create a large string. Split the string into individual values and calculate the average of all the values that aren't -901. Note: You can convert a string to a floating point value using the float() function. 71.6048

Please use python and show the code used.

Answer 1

Here's how you can solve these two problems. I have put comments so that its easier for you to understand
Let me know if you have any question. Keep learning and stay safe :)
PS: If you are satisfied with my answer, please consider voting it up. It really helps.

Question 1:

# Input data string
data = """63.7 67.7 67.9 76 -901 80.3
        -901 -901 81.3"""

# Split data by a " ", convert each item to float and store in a list called arr
arr = [float(x) for x in data.split()]

sum = 0
count = 0
for item in arr:
    # If item is not 901, consider for average
    if item != -901:
        sum += item
        count += 1

# Printing average
print("Average:", sum/count)


Question 4:

import math
import cmath

def sqrt(num):
    # If the number is positive, use math.sqrt
    if num >= 0:
        return math.sqrt(num)
    # If the number is negative, use cmath.sqrt
    elif num < 0:
        return cmath.sqrt(num)

# Driver code to test the above function
positive_num = 9
negative_num = -9
print("Square root of {}: {}".format(positive_num, sqrt(positive_num)))
print("Square root of {}: {}".format(negative_num, sqrt(negative_num)))

Output:

Lili Result Execute > Share main.py STDIN 1 # Input data string 2 data """63.7 67.7 67.9 76 -901 80.3 3 -901 -901 81.3""" $python3 main.py Average: 72.81666666666668 arr = sum = 5 # Split data by a " ", convert each item to float and store in a list called arr 6 [float(x) for x in data.split()] 7 8 0 9 count 10 - for item in arr: 11 # If item is not 901, consider for average 12. if item != -901: 13 sum += item 14 count += 1 15 16 # Printing average 17 print("Average:", sum/count)

Llı Result $python3 main.py Square root of 9: 3.0 Square root of -9: 3j Execute | Share main.py STDIN 1 import math 2 import cmath 3 4- def sqrt(num): 5 # If the number is positive, use math. sqrt 6. if num >= 0 : 7 return math.sqrt(num) 8 # If the number is negative, use cmath.sqrt 9. elif num < 0: 10 return cmath.sqrt(num) 11 12 # Driver code to test the above function 13 positive_num 9 14 negative_num = -9 15 print("Square root of {}: {}".format(positive_num, sqrt(positive_num>)) 16 print("Square root of {}: {}".format(negative_num, sqrt(negative_num>))