Question

Question 13 The 3.50 kg cube in the figure has edge lengths d = 7.20 cm and is mounted on an axle through its center. A spring (k = 1300 N/m) connects the cube's upper corner to a rigid wall. Initially the spring is at its rest length. If the cube is rotated 5.00° and released, what is the period of the resulting SHM? ROA d Number Units

Answer 1

Here,

k= 1300 N/m

Then,

solution : Here, M = 3.5 3-5 kg K = 1300 N/m L = 7•2 cm = 0.072 m using) 5° (small angle Now, The time period is; - T = үп II i. I = moment of inertia - ML² 12 so, = I = (3.5 kg) (0.072) 12 - I = 0.001512 kg m? -c = constant = *Z? 4 So, - C - ✓ (1300 N/m) (0.072)? = C = 1.6848

Now, Pot all valves in time period equation; - T - રે 0.001512 1.6848 = T = 0.188 sec (Answer)