Question

Q3: Determine the vertical and horizontal displacement of joint A for the truss shown in Fig. (3). cach bar is made of steel and has the cross-sectional area of 400mmº. Take E = 200 GP. Use the method of virtual work. 25%

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Answer 1

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Sol Peris? given truss analysis D let veactices at card Doue 24 Me , Vic & Hoilo as shown. 8 H с IN Netvo - Gokal- fokN 2 4 fanco: EM Mpx 2 20 X5+ to X3 [Ho He 7 pea B: point *FAB λοι3 at point A [FEB= 20kn FcfAB 30 KN FAE 1 - to @ pointe :- Не. FEC qol He = foc + feu cosco 40 75 = 30 + FECI FAL sinto FAG 4 / 40 V Mhe. = FEC. Since I Ve = - fae also Four eq = Netto FAO fe como 30 KN fre reo = Mo = 774)

So We have Actual Wirtual Member Porce A inx-direction n (H) (m) АО Virtual in 4-direction Efnil efnil= ng - 3/4 + 5/4 -30 1+ 33.75 45 +156-25 BE +20 2 0 0 BC - 30 ti 1.5 -3/4 45 1+ 33.75 CE -75 2.5 0 234.375 514 DE +95 +168.75 + 1.5 3-90 Z 626.875 For Now wring reinterd word ustel fer x displacemjestia Horo reactions at C& shown Met Ho Ho CC ch Ho f = 1kn EMO In 2 Hc X2 He kn at A:- point at pointe: pre Fen FAE I Fac be FEL Troc leng Foc He IN =) TTAE Theo Me - fecto IFAO = 1 aut D:- Teeze, Filling all values ein abowe tablelno)

Now нр Votle C ECO) Ne o FED FED = 1.5 km Hol-skan Jln all in na Column Filling Tor virtual work, in 4. direction.. FEC 5 Ho - He He = 1.5kn Ilu (1) Ho - 1.SIN FAE at FAB FAE Çoco1 FAL 5/44 FAC COD FDE FBC IFBE = 0 KN que at C: He-foc = Fec con 3 + ܒܝܬܐ 8 E FARE - 90 x 10 2 403 4g * * FAB Sx = -1,125 mm ly fac = FAB Sy AE 62.6.875 xx x 200x to OFIL He •FEL | sy 7.836 may e a Ffc sina S 4 Fec Ne - tin Vook