Question

an someone help? This problem still confuses me. Thank you.

An artide reported that, in a study of a particular wafer inspection process, 356 dies were examined by an inspection probe and 182 of these passed the probe (Give answers accurate to 3 decimal places) (a) Assuming a stable process, calculate a 95% (two-sided) condence interval for the proportion of all dies that pass the probe (45901 56300 (b) Assuming a stable process, calculate a 98% (two-sided) confidence interval for the proportion of all dies that pass the probe (4586

Answer 1

(6) Solution, n = 356 x = 182 Let ê be the sample propostion, 0.511 356 Ô = X = 182 Now, c = 98% = 0.98 x = -c = 1-0.98 0.02 2 2 = 0.02 = 0.01 using z table z = 0oT IN 2.326 2 H2 z Margin of error & - IÊ (I-Ê n -2.326 0.511 (1-0.54) 356 - 0.061 98% confidence interval is ête Ê - Ece<êt E 0:511-0.061 < p < 0.511 +0:061 0.45 < p < 0.57 (0.45 0.57) ta