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A sample of size 100 is selected from a population with p = .40. Use z-table. a. What is the expected value of p? b. What is
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a. The expected value of the \bar{p} is E(\bar{p})=p=0.40

b. The standard error of \bar{p} is , SE(\bar{p})=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.40(1-0.40)}{100}}=0.049

c. Normal distribution with E(\bar{p})=0.40 and \sigma_{\bar{p}}=0.049

d. It shown the probability distribution for the normal distribution.

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