Question

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<Homework 11 Exercise 15.18 - Enhanced - with Feedback 3 of 5 Review Constants How much time does it take a pulse to travel the full length of the string? Express your answer with the appropriate units. A 1.60 m string of weight 0.0125 N is tied to the celing at is upper and, and the lower and supports a weight Wignore the very small variation in tension along the length of the string that is produced by the weight of the string. When you pluck the string slightly, the waves traveling up the string by the equation y(xt) - (8.60 mm) cos (172 rad/m 2 - 4830 rad/st) Assume that the tension of the string is constant and equal to W I ? t = 0.1 S Submit Previous Answers Request Answ * Incorrect; Try Again; 6 attempto remaining urse Part B

Answer 1

a)The speed of the wave in the string is, V= k The time taken by the pulse to travel the full length of the string is, 2 V L k kL @ V= (172 )(1.60) 4830 = 0.0575 b)The lower weight is T u The tension in the wire will be equal to the weight of the hanging mass. T=W The linear mass density of the wire is, m u L w gZ The height is, VE u и II 1 gl 2 w W gl k 0.0125 (9.8 (1.60) = 0.628N 4830 172

c)The number of wavelength in that instant is, L = n2 L n= The wave number is, 21 k= 2 271 2= k The number of wavelengths is, L 21 k kz n = (172 )(1.60) 27 = 43.79944034 =44 d)The equation of the wave traveling down the string is, y(x,t)= (8.50mm)cos[(172 rad/m)x+(4830 rad/s)t]