H1= p 0.612 (this means, its a two tailed test)
Test statistic, z = -3.06
P- value = 2 P( z < -3.06 )
= 2* [ 1- P(z < 3.06)]
= 2 * [ 1- 0.99889]
= 2 * 0.00111
= 0.0022
Now, P-value < significance level ( 0.05) ; we will reject the null hypothesis
Answer- 4) 0.0022 ; reject the null hypothesis.
Question 21 (4 points) Use the given information to find the P-value. Also, use a 0.05...
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With Hy:p0.377, the test statistic is z = 3.06. O A. 0.0022; fail to reject the null hypothesis OB. 0.0011; reject the null hypothesis OC. 0.0022; reject the null hypothesis OD. 0.0011; fail to reject the null hypothesis
Question 18 (4 points) Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a two-tailed test is z = -1.63. 1) 0.9484; fail to reject the null hypothesis 2) 0.1032; fail to reject the null hypothesis 3) 0.0516; fail to reject the null hypothesis 4) 0.0516; reject the null hypothesis
Use the given information to find the P-value. Also, usw a 0.05 significance level and state the conclusion about the null hypothesis ( reject the null hypothesis or fail to reject the null hypothesis). With H1: p> 0.554, the test statistic is z = 1.34
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).The test statistic in a right-tailed test is z=0.52. A. 0.6030; fail to reject the null hypothesis B. 0.3015; reject the null hypothesis C. 0.0195; reject the null hypothesis D. 0.3015; fail to reject the null hypothesis
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With H :p> 0.554, the test statistic is z = 1.34. O A. 0.0901; fail to reject the null hypothesis O B. 0.9099; fail to reject the null hypothesis OC. 0.0901; reject the null hypothesis OD. 0.1802; reject the null hypothesis
Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis. With H PE 0.714, the test statistic is z = 2.21. O 0.0136; reject the null hypothesis 0.0136; fail to reject the null hypothesis 0 0.0272; reject the null hypothesis O 0.0272; fail to reject the null hypothesis.
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With Hy:p>0.554, the test statistic is z = 1.34. O A. 0.0901; reject the null hypothesis OB. 0.9099; fail to reject the null hypothesis OC. 0.0901; fail to reject the null hypothesis OD. 0.1802; reject the null hypothesis
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a right-tailed test is zequals=0.52.
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).With Upper H 1H1: pgreater than>0.554, the test statistic is zequals=1.34. A. 0.0901; reject the null hypothesis B. 0.0901; fail to reject the null hypothesis C. 0.9099; fail to reject the null hypothesis D. 0.1802; reject the null hypothesis
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With Upper H 1 : pgreater than 0.554, the test statistic is zequals 1.34. A. 0.0901; reject the null hypothesis B. 0.0901; fail to reject the null hypothesis C. 0.9099; fail to reject the null hypothesis D. 0.1802; reject the null hypothesis