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Question 21 (4 points) Use the given information to find the P-value. Also, use a 0.05 significance level and state the concl
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Answer #1

H1= p\neq 0.612 (this means, its a two tailed test)

Test statistic, z = -3.06

P- value = 2 P( z < -3.06 )

= 2* [ 1- P(z < 3.06)]

= 2 * [ 1- 0.99889]

= 2 * 0.00111

= 0.0022

Now, P-value < significance level ( 0.05) ; we will reject the null hypothesis

Answer- 4) 0.0022 ; reject the null hypothesis.

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