Question

Use the given information to find the

​p-value.

​Also, use a 0.05 significance level and state the conclusion about the null hypothesis​ (reject the null hypothesis or fail to reject the null​ hypothesis).

With

Upper H 1

​:

pgreater than

​0.554,

the test statistic is

zequals

1.34.

A.

​0.0901; reject the null hypothesis

B.

​0.0901; fail to reject the null hypothesis

C.

​0.9099; fail to reject the null hypothesis

D.

​0.1802; reject the null hypothesis

Answer 1

SOLUTION:

From given data,

Use the given information to find the ​p-value. ​Also, use a 0.05 significance level and state the conclusion about the null hypothesis​ (reject the null hypothesis or fail to reject the null​ hypothesis).With Upper H ₁ : p greater than ​0.554, the test statistic is  z equals 1.34.

Where,

significance level = = 0.05

test statistic = z =1.34

Test hypothesis:

H₀ : p = 0.554 (null hypothesis)

H₁ : p > 0.554 (Alternative hypothesis)

Using standard normal table,

P-value:

P-value = P(Z > 1.34)

P-value = 1 - P(Z < 1.34)

P-value = 1 - 0.90988

P-value = 0.0901

P-value = 0.0901 > significance level = = 0.05 then

fail to reject the null hypothesis.

Answer : Option (B)

​0.0901; fail to reject the null hypothesis

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