Use the given information to find the p-value. Use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).
a. The test statistic in a right-tailed test is z = 1.00.
b. The test statistic in a test with alternative hypothesis p 6= 5/7 is z = 2.05.
c. The test statistic in a test with alternative hypothesis p < 2/3 in z = −0.45.
a) for right tailed test and given test statistic ; p value =P(Z>1) =0.1587
since p value >0.05 , fail to reject the null hypothesis
b)
for two tailed test and given test statistic ; p value =2*P(Z>2.05) =2*0.0202 =0.0404
since p value <0.05 , reject the null hypothesis
c)
for left tailed test and given test statistic ; p value =P(Z<-0.45)=0.3264
since p value >0.05 , fail to reject the null hypothesis
Use the given information to find the p-value. Use a 0.05 significance level and state the...
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).The test statistic in a right-tailed test is z=0.52. A. 0.6030; fail to reject the null hypothesis B. 0.3015; reject the null hypothesis C. 0.0195; reject the null hypothesis D. 0.3015; fail to reject the null hypothesis
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a right-tailed test is zequals=0.52.
Use the given information to find the P-value. Also, usw a 0.05 significance level and state the conclusion about the null hypothesis ( reject the null hypothesis or fail to reject the null hypothesis). With H1: p> 0.554, the test statistic is z = 1.34
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Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With H :p> 0.554, the test statistic is z = 1.34. O A. 0.0901; fail to reject the null hypothesis O B. 0.9099; fail to reject the null hypothesis OC. 0.0901; reject the null hypothesis OD. 0.1802; reject the null hypothesis
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Use the information given below to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a left-tailed test is z= - 1.29. What is the P-value? P-value = (Round to four decimal places as needed.) p-p Find the value of the test statistic z using z pa n The claim that the proportion of peas with yellow...
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).With Upper H 1H1: pgreater than>0.554, the test statistic is zequals=1.34. A. 0.0901; reject the null hypothesis B. 0.0901; fail to reject the null hypothesis C. 0.9099; fail to reject the null hypothesis D. 0.1802; reject the null hypothesis
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