Use the information given below to find the P-value. Also, use a 0.05 significance level and...
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).The test statistic in a right-tailed test is z=0.52. A. 0.6030; fail to reject the null hypothesis B. 0.3015; reject the null hypothesis C. 0.0195; reject the null hypothesis D. 0.3015; fail to reject the null hypothesis
Use the given information to find the p-value. Use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). a. The test statistic in a right-tailed test is z = 1.00. b. The test statistic in a test with alternative hypothesis p 6= 5/7 is z = 2.05. c. The test statistic in a test with alternative hypothesis p < 2/3 in z = −0.45.
1.) Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a two-tailed test is z = 1.95. Group of answer choices 0.0256; reject the null hypothesis 0.9744; fail to reject the null hypothesis 0.0512; reject the null hypothesis 0.0512; fail to reject the null hypothesis 2.) Use the confidence level and sample...
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a right-tailed test is zequals=0.52.
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With H :p> 0.554, the test statistic is z = 1.34. O A. 0.0901; fail to reject the null hypothesis O B. 0.9099; fail to reject the null hypothesis OC. 0.0901; reject the null hypothesis OD. 0.1802; reject the null hypothesis
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With Hy:p>0.554, the test statistic is z = 1.34. O A. 0.0901; reject the null hypothesis OB. 0.9099; fail to reject the null hypothesis OC. 0.0901; fail to reject the null hypothesis OD. 0.1802; reject the null hypothesis
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With Hy:p0.377, the test statistic is z = 3.06. O A. 0.0022; fail to reject the null hypothesis OB. 0.0011; reject the null hypothesis OC. 0.0022; reject the null hypothesis OD. 0.0011; fail to reject the null hypothesis
Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis. With H PE 0.714, the test statistic is z = 2.21. O 0.0136; reject the null hypothesis 0.0136; fail to reject the null hypothesis 0 0.0272; reject the null hypothesis O 0.0272; fail to reject the null hypothesis.
Use the given information to find the P-value. Also, usw a 0.05 significance level and state the conclusion about the null hypothesis ( reject the null hypothesis or fail to reject the null hypothesis). With H1: p> 0.554, the test statistic is z = 1.34
Question 18 (4 points) Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a two-tailed test is z = -1.63. 1) 0.9484; fail to reject the null hypothesis 2) 0.1032; fail to reject the null hypothesis 3) 0.0516; fail to reject the null hypothesis 4) 0.0516; reject the null hypothesis