Question

Solve the equation on the interval so<2. 8 sin 20 -2=0 What are the solutions in the interval Os8<2x? Select the correct choice and fill in any answer boxes in your choice below. O A. The solution set is (Simplify your answer. Type an exact answer, using as needed. Type your answer in radians. Use integers or fraction Use a comma to separate answers as needed.) OB. There is no solution.

Answer 1

Given 8 Sin²o-2=0 0=0 < 2T > 8 Sinto-2=0 8 sin?o=2 Sin²o. 2 8 Sin2o 4 - Sino = 4 Sino = 1 VA Sino=+ 2 Take 1 2 & Sino = Sm (11-0) = o = sin ' ( 12 ) 1-0 - Sin (1)

- Sin 6 U 0 = Sim-(einF IN-O - Gm(3m) 1 8=프 6 ㅂ 6 TI 야T 6 부여 6 6T-T 6 -) 야 6 57 야 5

Take Sino- - 1 Sin O= - 12 { - Sint 6 > Smo - Gin T 6 So write as - Sino = sin(-+ ) = sin(27- =) Sino = sin(177) = sin IT 6 So 71 6 6 The solution set is T 5T 66 ITT 6. 6