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Use the References to access important values if needed for this question. When 22.0 mL of a 5.45*10-4 M ammonium sulfide sol
The answer is not 2.4 x 10^-9.
Here is an example on how to do these type of problems.

Use the References to access important values if needed for this question. When 12.0 mL of a 3.22x104 Mpotassium sulfate solu
Step 1: Determine the number of moles of each ion used. 5.33x10-4 moles Ba2+ moles Ba2+ - x 0.0120 L Ba(OH)2 solution 6.40x10
Vfinal -0.0120 L + 0.0120 L -0.0240 L total. 6.40x10-6 moles Ba2+ [Ba2+). 2.67*10* M Ba2+ 0.0240 L 3.86x10-6 moles so, [SO42-
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