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To find the distance from the house at A to the house at B, a surveyor measures the angle ACB, which is found to be 10°, and
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C. A B qoft 100 goft C LCaloo 2 a Ac² + AC = 4oft Bergoft By cosine rule AB² B C² - 2xAC XBCX Case =) AB²=402 +90² 2x40x yox

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