Question

C. Here are some equipotential lines. OV 1 cm 1. Calculate the strength of the electric field at point X. Show your calculation. 2. At point X, the electric field points [t, , 1,7,7,7,V, KI 3. A negatively charged particle at X will feel a force pointing (4, 6, 1, 7, 1, 1, 3 4. Assume that the potential and field that the particle feels at X are caused by positive charges. Therefore, the potential (potential, not potential energy) at X is positive. Therefore, the system's potential energy when the particle is at X is (negative, positive, zero). 5. If the particle starts from rest, that negatively charged particle will begin to move from higher to lower, lower to higher electric potential (potential, not potential energy). 6. Therefore, as the negatively charged particle moves in that direction, the system's potential energy (energy, not potential) will increase, decrease, maintain a constant value and the system's kinetic energy will increase, decrease, maintain a constant value). Assume that this negatively charged particle is the only thing in the system that moves.

this is one question with many parts

Answer 1

son 1 ) let distance between, ov and 50V electric potential line is g = 1 cm Hence Electric field is E=AV. oy. ay = 1x10^2 kcm/ m Ov=50-0 Sov. E = 50 10-2 5000 /m. 2) Since the direction of electric field is from higher. Electric potential to Lower electric potention. so direction of of arrow at x is pointing upward Î E Х so . 3). Negatively Chorge -q present - Hence force Fe =-VE direction of Force Fe is pointing down Ward | Fe Х | Fe 4) If at & the potential is v>o, then potential energy et of particle at x ix u=qW when > Uno qco ) VO v=0 2 VO 5) A negatively Chorged portile move opposite to Electric field. from. Low electric potential to higher electric potentials i

6) As As we know As AU=-w) { change in potential energy = oou by conservative force negatively charge porticle moush W} for work done i's W along force hence (woo from equation 6 Buco hence potential energy decreases. Also mechanical energy Aktov > Cortant is zero. as work done by conservative force. ok=-ov ie Ek>o. so ok touto Ov hence charge in Kinetic energy ok >o so Kinetic Energy of particle will increase