A 3.9 kg block is being pushed across a frictionless horizontal surface by a horizontal force. The block accelerates at 5.6 m/s2. What is the magnitude of the normal force the surface exerts on the block? Express your answer in newtons and round to one decimal place.
Since block is on horizontal surface Normal force on block will be due to weight of block.
So,
N = mg
N= 3.9×9.8
N= 38.22 Newton. .......................... Answer
A 3.9 kg block is being pushed across a frictionless horizontal surface by a horizontal force....
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