A 2.0 kg block starts from rest. It is pushed across a rough horizontal surface by a force F (magnitude of F = 8.0 N) directed at a 40° angle as shown. The block is found to accelerate along the surface at 2.0 m/s2.
Prove that there is a frictional force acting on the block
If friction does not present,
Fnetx = F*cos(40)
m*a = 8*cos(40)
a = 8*cos(40)/m
= 8*cos(40)/2
= 3.064 m/s^2
but the acceleration given is 2 m/s^2 < 3.064 m/s^2.
so, there is firstiobnal force , fk = m*(3.064 - 2)
= 2*(3.064 - 2)
= 2.128 N
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