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On a rainy day, a car exits the interstate onto a ramp that spirals down to the street with a radius of R= 100 m. The advisor

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\! \! \! \! \! \! \! \! \! $Centripetal force required to move in a curve of radius R, $F_C = \frac{mv^2}{R}\\\\ $This centripetal force is provided by the frictional force between the tire and the road.$\\\\ $Maximum frictional force between the tire and the road is given by, $\\\\ F_f=\mu_s N = \mu_s mg\\\\ F_C = F_f \;\;\Rightarrow \;\; \frac{mv^2}{R}= \mu_s mg\;\;\Rightarrow \;\;v=\sqrt{\mu_sRg}\\\\ v = \sqrt{0.5\times 100\times 9.8}=22.14$m/s $ = 49$mph$\\\\ $Option C is correct.$

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