Time period of a planet whose semi axis is 3.5×10⁹m is found to be 100 years. Find the time period of a planet whose semi axis is twice of it.
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a) Calculate the period T of a planet whose orbit has a semi semimajor axis of 16 AU. _______ y b) Calculate the period T of a dwarf planet whose orbit has a semimajor axis of 662 AU. _______y c) Calculate the period T of a planet whose orbit has a semimajor axis of 5.3 AU. _______ y
A)Some comets are in highly elongated orbits that come very close to the sun at perihelion. The distance from one such comet to the center of the sun is 6.00×10^9m at perihelion and 3.00×10^12m at aphelion. For this comet's orbit, find the semi-major axis. B) In 2017 astronomers discovered a planet orbiting the star HATS-43. The orbit of the planet around HATS-43 has semi-major axis 7.41×109m, eccentricity 0.173, and period 4.39 days. Find the distance between HATS-43 and the planet...
MI Review | Constants Periodic Table wnat is the semi-major axis of the planer's ordit? A new extrasolar planet (outside our solar system) has been discovered. This planet orbits a star of mass 1.00x1031 kg with a period of 6.52 years. It is also known that the planet has an eccentricity of 0.684. ► View Available Hint(s) IVO AXO ? Semi -major axis = m Submit Previous Answers X Incorrect; Try Again; 5 attempts remaining Part B What is the...
correct Question 22 0/2 pts Consider a hypothetical planet in our solar system whose average distance from the Sun is about twice as that of Earth. What is the orbital period for this hypothetical planet is the period for Earth is 1 year. 1 year 8 years 2 years 4 years
A new extrasolar planet (outside our solar system) has been discovered. This planet orbits a star of mass 1.03×1031 kg with a period of 6.52 years . It is also known that the planet has an eccentricity of 0.694. Part A Part complete What is the semi-major axis of the planet's orbit? View Available Hint(s) Semi−majoraxis= 9.03×1011 m SubmitPrevious Answers Correct Part B What is the average velocity of the planet in its orbit Part C What is the distance of closest approach to its...
In 2017 astronomers discovered a planet orbiting the star HATS-43. The orbit of the planet around HATS-43 has semi-major axis 7.41×109m, eccentricity 0.173, and period 4.39 days. Find the mass of HATS-43.
I need to prove Keplers laws with calculus. 1.- The orbit of a planet is an ellipse with the Sun at one of the two foci. 2.- A line segment joining a planet and the Sun sweeps out equal areas during equal intervals of time. 3.- The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.
The minor planet (33340) 1998 VG44 makes exactly two orbits of the sun during the time that Neptune makes three orbits. The eccentricity of the orbit of this minor planet is 0.25, and the orbit radius of Neptune is 4.5×1012m. Find the semi-major axis of this minor planet
A resonance orbit is one in which planets have a fixed ratio of orbital periods. For example, for 2 planets with an orbital resonance of 3:1, the outer planet's orbital period would be 3 times that of the inner one. That is, the inner planet can complete 3 exact orbits whilst the outer one completes only one. This is a special type of orbital "locking". The two planets orbiting the nearby star are observed to be in a 2:1 resonance...
Question 7 (0.5 points) What causes the Moon to move about 12° across the sky from one night to the next (at the same time of night, of course)? O Because the Earth is turning on its axis. O Because the Moon is moving in its orbit. The Sun has also moved 15° across the sky and gravitationally pulls the Moon with it. The celestial sphere the Moon is attached to has moved 15°. O It is an optical illusion....