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For Questions 11-15, consider the following: The Human Resource Manager of a large insurance company wishes to evaluate the l
Supervisor Mid-Manager Upper-Manager 33 29 32 43 36 39 34 32 40 29 36 46 ---- ANOVA TABLE Sources of Variation SS df MS F p-v
Total 2112 35 The critical value of the ANOVA test at 1% alpha is: O 6.25 O 3.28 O 5.31 O 4.38 5.61
How much variation (in terms of Sum of Squares) is explained by position of the managers? O 1716 O 2112 O 198 O 52 0 396
What is the mean square error for within groups? O 1716 O 2112 O 396 O 198 O 52
Assume that the calculated value of the test statistic is 6. What is the conclusion for the ANOVA test? Use the critical F-va
Assume that the p-value associated with the test statistic is 0.005. What is the conclusion for the ANOVA test? Use the alpha
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Answer #1

The complete_ANOVA table by using formula MS. SS OP MSBEtween MS within F froit = F(2,33,0.01) - 5:31 SS df MS Source of vari= Assumed p-value = 0.006 andd 30.01 > p-value = 0.005 <0=0.01 Reject HO Not all manager gooups have the same Jeadership

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