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The Human Resource Manager of a large insurance company wishes to evaluate the leadership qualities of 3 manager groups- supePart 1 of 5: The critical value of the ANOVA test at 5% alpha is: 4.38 6.25 5.61 5.31 3.28Part 2 of 5: How much variation (in terms of Sum of Squares) is explained by position of the managers? 396 52 2112 198 1716Part 3 of 5: What is the mean square error for between groups? 1716 198 396 52 2112Part 4 of 5: Assume that the calculated value of the test statistic is 6. What is the conclusion for the ANOVA test? Use thePart 5 of 5: Assume that the p-value associated with the test statistic is 0.005. What is the conclusion for the ANOVA test?

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# dif. MS Feritical Given that! ss A NOVA_TABLE Source of Variance 396 ss Between Groups 1746 396 within Groups 1716 Total 21classmate Date Page Hoi Mi=l2 = 13 للدولههد P-value = 0.0005 (Assumed) x=0.05 p-value &x=0.05 i ( significat) Hence we reject

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