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Question 7 (1 point) A simple random sample of 18 statistics students is chosen. If the previous semesters student evaluatio
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Answer #1

Solutions
Given:
n= 18,

p= 30%=0.30
X~ binomial distribution (n=18,p=0.30)
The pmf of the binomial random variable is given by
P(X=x)= (nCx) (p^x) [q^(n-x)] , where q=1-p
=(18Cx)(0.30^x) [0.70^(18-x)]
b)P(X<=2)= P(X=0)+P(X=1)+P(X=2)
=(18C0)(0.30^0) [0.70^(18-0)]
+(18C1)(0.30^1) [0.70^(18-1)]
+(18C2)(0.30^2) [0.70^(18-2)]
=(1)(1)(0.70^18)
+(18)(0.30)(0.70^17)
+(153)(0.30^2)(0.70^16)
=0.0016+0.0126+0.0458
=0.06
P(X<=2)=6%
The probability that no more than 2 students in the sample do not favour an online course format is 6%

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