Solution :
mean = = 545.3
standard deviation = = 29.9
a ) P (x 551 )
= 1 - P (x 292 )
= 1 - P ( x - / )( 551- 545.3 / 29.9)
= 1 - P ( z 5.7 / 29.9 )
= 1 - P ( z 0.19)
Using z table
= 1 - 0.5753
= 0.4247
Probability = 0.4247
b ) n = 30
= 545.3
= / n = 29.9 30 = 5.4590
c ) = 551
Using z-score formula,
z = - /
z = 551 - 545.3 / 5.4590
= 5.7 / 5.4590
=0.91
z = 0.91
d ) P (x 551 )
= 1 - P (x 292 )
= 1 - P ( - / )( 551- 545.3 / 5.4590)
= 1 - P ( z 5.7 / 5.4590 )
= 1 - P ( z 1.04)
Using z table
= 1 - 0.8508
= 0.1492
Probability = 0.1492
Chapter 7: Problem 13 Previous Problem Problem List Next Problem (1 point) The scores of students...
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