Homework Answers
P(E) = 0.24
P( F) = 0.41
a) P( E and F) = P( E n F) = 0 ; As E and F are mutually exclusive
b) P( E |F) = P( E n F) / P( F) = 0 / 0.41 = 0
c) P( E or F) = P(E) + P(F) = 0.24 + 0.41 = 0.65
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