Question

HOW TO MAKE TR... pearson monetary policy pr... Region Search ED... ent 6 (Ch 6) 0 Saved Help b. What are the mean and the standard deviation for the distribution? (Round your answers to 2 decim places.) Mean Standard deviation OK ences c. Calculate PXS-1). (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.) PIXS-1) Prev 2.06 HB Next > 3 1723 Prisc Insert % Delete 2 3 $ 4 5 6 & 7 8 9 ) 0 Backspace Lock W E R Y O S e D G Н. c K Enter Х С V B N М. Shift End Alt Alt + TPgUp Ctrl

please give simple explanation and steps

Answer 1

c ) P(XS-1) P|X(+) s flu).du - 5 P(X(-1) = 5' 1 du X{-1). PL 1/2 (-1+5) = T2 P(X(-1) = 1 = 0.333 3

Solution. heti Random nariable x was the continuous uniform distrubation with lower bound b=7 follows Lipper bound f(ut sua Area = base & xheight base- height br a a) what is height of density funneti height= f(u) -s<n<12 12 othluulte height flus= 1/2 = 0.08333 b) Mean = atb 27:21 atb. 2 nean = u=1 Standar deviation - I variance - a b-a)² 12 S.D=512 s Landard Deniation = 3.464.