Problem 6: Now, find the following probabilities. Remember to ask yourself the questions,
Enter your answers as reduced fractions using / as the fraction bar.
(i) P(K and K) = (4/52) * (4/52) = 16/2704 =
1/169.
(ii) P(R or B) = (26/52) + (26/52) = (1/2) + (1/2) =
1/1.
(iii) P(red queen and black queen) = (2/52) * (2/52) = 4/2704 =
1/676.
(iv) P(K and K) = (4/52) * (3/51) = 12/2652 =
1/221.
(v) P(heart) = 13/52 = 1/4.
(vi) P(drawing a face card) = 12/52 = 3/13.
(vii) P(an ace, a 2 and a 3) = (4/52) * (4/51) * (4/50) = 64/132600
= 8/16575.
(viii) P(a Club or 7) = (13 + 4 - 1)/52 = 16/52 =
4/13.
(ix) P(an ace, a 2 or a 3) = (4/52) + (4/52) + (4/52) = 12/52 =
3/13.
Problem 6: Now, find the following probabilities. Remember to ask yourself the questions, Is this a...
Problem 6: Now, find the following probabilities. Remember to ask yourself the questions, Is this a simple or compound probability?How many cards are being drawn?Which conjunction is used and should we add or multiply?If it is a compound probability, are the events dependent, independent, mutually exclusive, or not mutually exclusive?Which formula should be used?Enter your answers as reduced fractions using / as the fraction bar. What is the probability of drawing a king, replacing it, and then another king? ?(?????)=P(KandK)= AnswerWhat is the probability of drawing a...
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