Consider a 100.0 mL sample of 0.0200 M Ni(NO3)2. Then 10.0 mL of 0.300 M NH3 is added. What are the molar concentrations of Ni2+, NH3, and [Ni(NH3)6]2+ at equilibrium?
Kf for [Ni(NH3)6]2+ = 2.0 x 10^8
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Consider a 100.0 mL sample of 0.0200 M Ni(NO3)2. Then 10.0 mL of 0.300 M NH3...
Consider a 100.0 mL sample of 0.0200 M Ni(NO3)2.. Then 10.0 mL of 0.300 M NH3 is added. What are the molar concentrations of Ni2+, NH3, and [Ni(NH3)6] 2+ at equilibrium? Kf for [Ni(NH3)6] 2+ = 2.0 x 10^8
Consider a 100.0 mL sample of 0.0200 M Ni(NO3)2.. Then 10.0 mL of 0.300 M NH3 is added. What are the molar concentrations of Ni2+, NH3, and [Ni(NH3)6]2+ at equilibrium? Kf for [Ni(NH3)6]2+ = 2.0 x 108
Consider a 100.0 mL sample of 0.0200 M Ni(NO3)2.. Then 10.0 mL of 0.300 M NH3 is added. What are the molar concentrations of Ni2+, NH3, and [Ni(NH3)6]2+ at equilibrium? (8 pts) Kf for [Ni(NH3)6]2+ = 2.0 x 108 PLEASE EXPLAIN, THANKS
2. Consider a 100.0 mL sample of 0.0200 M Ni(NO3)2. Then 10.0 mL of 0.300 M NH3 is added. What are the molar concentrations of Ni2+, NH3, and [Ni(NH3).]* at equilibrium? (8 pts) Krfor [Ni(NH3).]?* = 2.0 x 108
2. Consider a 100.0 mL sample of 0.0200 M NI(NO3)2. Then 10.0 mL of 0.300 M NH3 is added. What are the molar concentrations of Ni2+, NH3, and (Ni(NH3).]” at equilibrium? (8 pts) K for [Ni(NH3).)?* = 2.0 x 108
i just want to know if i need to divide the concentration for Ni(NO3)2 in half because the molar ratio isnt 1:1. i dont need this problem to be solved. 2. Consider a 100.0 mL sample of 0.0200 M NI(NO3)2. Then 10.0 mL of 0.300 M NH3 is added. What are the molar concentrations of Ni2+, NH3, and (Ni(NH3).]” at equilibrium? (8 pts) K for [Ni(NH3).)?* = 2.0 x 108
When 0.1 L of 0.0200 M Ni(NO3)2 is combined with 0.010 L 0.3 M NH3, the Ni(NH3)62+ ion forms (Kf = 2.0 × 10^8). Calculate the equilibrium concentration of Ni2+, NH3, and Ni(NH3)62+
2. You mix a 105.0 mL sample of a solution that is 0.0114 M in Ni(NO3)2 with a 190.0 mL sample of a solution that is 0.300 M in NH3. After the solution reaches equilibrium, what concentration of Ni2+ remains? The value of Kr for [Ni(NH3)6]2+ is 2.0x108.
One millimole of Ni(NO3)2 dissolves in 230.0 mL of a solution that is 0.300 M in ammonia. The formation constant of Ni(NH3)62+ is 5.5×108. What is the initial concentration of Ni(NO3)2 in the solution? I already have this answer which is 4.35E-3, but I cannot figure out the second part which is: What is the equilibrium concentration of Ni2+(aq ) in the solution? and the answer IS NOT 1.08E-8
06 Question (2 points) One millimole of Ni(NO3)2 dissolves in 240.0 mL of a solution that is 0.300 M in ammonia. The formation constant of Ni(NH3)62+ is 5.5x108. 1st attempt Part 1 (1 point) What is the initial concentration of Ni(NO3), in the solution? M Part 2 (1 point) What is the equilibrium concentration of Ni2+(aq) in the solution?