Homework Answers
| location | A | B | C | D | E | total |
| student | 312 | 250 | 205 | 160 | 350 | 1277 |
| teacher | 13 | 10 | 9 | 6 | 15 | 53 |
| HHN-1 | ||||||
| Quota | 0.9848 | 0.7575 | 0.6818 | 0.4545 | 1.13 | |
| Lower Quota | 0.9 | 0.7 | 0.6 | 0.4 | 1 | |
| Goemetric mean | 1.80 | 1.09 | 0.9797 | 0.7488 | 1.414 | |
| Final Appointment | 2 | 1 | 0 | 0 | 1 | 4 |
Let D= be divisor = total teacher/ no of teachers appointed = 53/4=13.2
Quota = no of teacher present in current location/ D
Lowe Quota= Floor(Quota)
Geometric mean = sqrt(n(n+1) , where n=lower quota
Rule of selection =
If Quota > Genometric mean ----round up
if Quota <Geometric mean ----round down
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limitations to your solutions. The case analyses serve to:
a) Provide an opportunity to apply the class concepts in the
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b) Provide you with a common task through which you can learn to be
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The
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