Question

1) Determine the force in members GE, GC and BC of the truss shown below. Indicate whether the members are in tension or compression. E 50ON Зим T I o e A G 1-3mt sm 3m- 1400N

Answer 1

Solution:- Stept:- calculate support reactions at joint A and Dir a G. E Equilibrium equations:- SOON 3m į EMA=0;- D Asc A B a 1400XB- Ay 1400N Dyx(8+3) +500x3=0 Dy om 3m Dy = 115405N :: tano- ji) EFx=0; Ax +500=0 Ax = -SOON 0=31° sino=0:51 COSO = 0.86 ily Efy=0 Ay -1400 + Dy=0 Ay => Ay = 245.5N steps: cut a Cut a section at a-a' and method of section, calculate forces in Members: - Equilibriun equations:- G ij EMGO (Net moment about 1 500NS point G=0 :B 245:5N 10 FGE 3m F G C FBC kon

E: => FBCX3 - 500x3 245.5X3 = 0 FBc = 7455N Tension Gary Efy=0; (Net Verticle force =o) → 245.5 - Fac sino 20 FGc= 245.5 0.51 FGC = 481-37N Tension Lary i) Efx=0;- (Net horizontal force = o) → Foct Fac coso + FGE-500 =0 => 745.5+481:37 X0.86+ FGE-500 =0 FGE= - 659.5N compression Note: If force in a member has sign: - tve: Tension - Ve : compression.
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