Question

A racing car travels on a circular track with a radius of 225 m. If the car moves with a constant linear speed of 47.0 m/s, find (a) its angular speed and (b) the magnitude and directions of its acceleration. O(a) 0.209 rad/s; (b) 9.82 m/s2 in the direction of tangential velocity i O(a) 0.709 rad/s; (b) 47.0 m/s2 in the direction of tangential velocity • (a) 0.209 rad/s; (b) 9.82 m/s2 toward the center of the track O(a) 4.79 rad/s; (b) 9.82 m/s2 toward the center of the track (a) 0.209 rad/s; (b) 47.0 m/s2 in the direction of tangential velocity *

Answer 1

By using basic circular motion physics we calculate the angular velocity.

We know that when both linear and angular velocity is constant then linear or tangential and angular acceleration is zero.

So we calculate the centripetal acceleration which is acting towards the centre.

Salt 2251 o= uniomis constant av hat ਦੀ 15 As we know for circular motion, rxw т/с u7io 225 = 0.209 rady =) u= € oust at = 0 (tangential acco) we constant - a=0 radial acceleration Angular alo only centripetal ace is there (radial aca) a = (47) 9.8/7radla २१७ a = towards cente = 9.82 rad 1² Scanned By SelfScan