Question

In standardizing an examination, the average score on the exam must be known in order to differentiate among examinees taking the examination. The scores recorded for a sample of 93 examinees yielded a mean and a standard deviation of 67.5 and 8.2, respectively. Estimate the true mean score for this examination and calculate the margin of error in estimation.

a.) μ =

b.) σ x ¯ =

c.) margin of error = ±

In standardizing an examination, the average score on the exam must be known in order to differentiate among examinees taking the examination. The scores recorded for a sample of 93 examinees yielded a mean and a standard deviation of 67.5 and 8.2, respectively. Estimate the true mean score for this examination and calculate the margin of error in estimation. 0 H = Select] 67.5 1.67 6277.5 762.6 0.08 0.85 mar 7.0 0.726

Answer 1

Sel (a) u 67.5 167 - 1 10.95 In 593 93 engor, E = Za tap, not x margin of er where, talin-1 = 1.92 to-025, 92 E = 1.98* 0.85 1.67 CS Scanned with CamScanner