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Question 11 How can you apply the 2nd Law of Thermodynamics to your life? (1 point)*...
Question 12 When delta G is negative (1 point)* entropy is high and enthalpy low entropy low and enthalpy high when entropy is negative when entropy is zero Question 13 Question 13 When delta G is negative (1 point) * O initial G is high and final G is low initial G is low and final G is high intial G is in equilibrium with final G O none Question 14 When delta G is negative (1 point) * O...
when entropy is zero Question 13 When delta G is negative (1 point) * initial G is high and final G is low initial G is low and final G is high Intial G is in equilibrium with final G none Question 14 When delta G is negative (1 point)* All of the above O system has low entropy system is at equilibrium Othere is an attractor operating in the mechanism
Question 9 Third Law of Thermodynamics states entropy is _when at zero kelvin and in a crystal (1 point) * infinite none one O zero Question 10 Second Law of Thermodynamics states entropy is ___always for the Universe (1 point) infinite O negative O positive O zero
Question 5 When delta G is negative (1 point) * enthalpy is negative reaction is spontaneous rx is at equilibrium rx is non-spontaneous Question 6 If a rx has delta S positive and delta H negative, the rx is (1 point) * non-spontaneous at all temp O spontaneous at all temp spontaneous only at high temp O spontaneous only at low temp
Question 15 When delta G is negative (1 point) * None of the above O reaction is balanced in mass and energy O reaction is endothermic if entropy is positive reaction is exothermic if entropy is positive Question 16 When delta G is negative (1 point) * O None reactions are spontaneous because they were empirically determined and consistent with the theory Orx is at equilibrium Orx is non-spontaneous
1.The spontaneity of system or a biochemical reaction can be determined by: A) Enthalpy alone B) Entropy alone C) Gibbs Free energy D) Temperature and heat 2.A reaction in equilibrium where both forward and reverse reactions are proceeding equally, will have a DELTA G value of: A) Positive B) Zero C) Negative 3.A reaction was originally endergonic, but became exergonic after reducing the temperature. Therefore, this reaction originally had __________ deltaH and a ______ delta S. A) small positive, large...
HELP!!!!! as soon as possible Question 9 (1 point) Which of the following reactions would show an increase in entran apply. O CaCO3 (s) CaO (s) + CO28) C6H6(s) C6H6() 4 NO (g) + 6 H20 (8) 4 NH3(g) + 5 O2 (g) 2 NIS (s) + 3 O2 (g) - 2 SO2(g) + 2 NIO (s) 2503(9) 2SO2(g) + O2(g) 3 Question 8 (1 point) Which of the following has the highest entoon C6H12(l) at 200 K in a...
Thermodynamics example information to help solve each question CALCULATIONS Question 1. Write the complete expression for the free energy change of the L = V equilibrium reaction for pure water (equation 2) at 100 bars and 300-C using the following data: Gy = -210330 joules/mole GL = -210330 joules/mole Recall that the right side (water vapor) of the reaction is the product side and left side (water liquid) of the reaction is the reactant side, Recall that we always calculate...
can you answer questions 7, 10, 11 and 13. thanks! Question Completion Status: QUESTION7 Refer to the following figure showing the reaction functions of oligopoly firms A and B OR, BR Bs Advertising In Nash equilibrium, both firms are maximizing their own profits given the level of advertising expected to be undertaken by the other firm O firm B can increase its profit by unilaterally increasing its level of advertising O firm A can increase its profit by unilaterally increasing...
THERES MORE THAN ONE PICTURE. I NEED ALL ANSWERED THANK YOU QUESTION 2 Calculate the pOH of a solution at 25.0°C that contains 2.95 x 10-12 M hydronium ions. 2.95 O 11.53 12.00 O 7.00 2.47 QUESTION 1 An aqueous solution at 25.0°C contains [H') -0,085 M. What is the pH of the solution? O 13.0 O 0.9850 O 1.07 O 1.20 10-13 O -1.07 QUESTION 2 10-12 M hydronium ions. Calculate the pOH of a solution at 25.0°C that...