Question

Question 14 8 pts A laboratory tested a sample of 100 chicken eggs and found that the mean amount of cholesterol was 257 milligrams; the population standard deviation for alleggs is 15.2 milligrams. Use this data to construct a 95 percent confidence interval for the true mean cholesterol content of all such eggs. (251.02.262.981 1255.02.261.981 1249.02, 264.98) (254.02, 259.98) Question 15 8 pts A group of 19 randomly selected students from a state university has a mean age of 224 years with a standard deviation of 3.8 years. Use this sample data to construct a 90% confidence interval for the mean age of all students at this university. (18.888.25.9121 (16.888.27.912) (21.888.22.9121 120.888.23.912) Question 16 8pts

Answer 1

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​​​​​​Here , critical values calculate from standard normal distribution table and t-distribution table.

"enlivo page solution- Que. 14). given that, sample size: na 100 sample mean= x= 257 , population standard = 3= 15.2 deyalton confidence send oogs Tevel of significance - f = 0.05 95% confidence internal for population mean is is, n (z togs & (257 S7 t l.g6 15.2 Voo 257-2.972 257+ 2.9 792) (254.0208, 259.9192) (254-02, 259.98) option D). (254.02, 259.98) is comeat Que. 15): given that, samplesize=n=19 sample mean = x= 22.4 sample standard deviation = 3.8 confidence level = oogo sevel of significance = 0.10 i go% confidence interial for population mean it is ř + teen s 22.4 I toos, 18 3.8 the | 22 2204 & 1.734 3.8 l 179 (22.4-1.512, 22.4+ 1.512) 20.888 23.9/2) correct option is D). (20.888, 23.972)

nlivo Date Page Que: 1 2) given that Samole size = n = 30 samole mean = x=913 sample standard deviation = 5 = 6.6 confidence level B.go d = clevel of significance = 0.10 90% confidence internal for population mean y. & to.1% in 91.3 t toos, 29 √30 gl.3 1.699 /30 ( 918 gles- 2.047, 91:2+ 2.047) ( 89.253 93.347 correct option is ( 89.253, 93.347)