H0: p 0.01
Ha: p > 0.01
Test statistics
z = ( - p ) / sqrt [ p ( 1 - p) / n ]
= ( 0.03 - 0.01) / sqrt ( 0.01 (1 - 0.01) / 600)
= 4.92
p-value = P(Z > z)
= P(Z > 4.92)
= 1 - P(Z < 4.92)
= 1 - 1
= 0
Since p-value < 0.01 level, reject the null hypothesis.
We have sufficient evidence to support the suppliers claim.
3) 3) A supplier of digital memory cards claims that no more than 1% of the...
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