You plate colonies of E. coli with the lac operon genotype of I+P+OCZ+CAP+ on 1) a medium containing only glucose, and 2) a medium containing only lactose. You isolate mRNA from bacteria from each medium and do a Northern blot with a probe for β-galactosidase. Draw the results.
Structure of wild type lac operon-
lacI+ |
CAP site |
Promoter |
lac Operator |
lac Z+ |
Lac Y+ |
lacA+ |
lacI gene encodes the repressor which blocks the transcription of lac structural genes (Z,Y,A) when bound at the lac operator site.
CAP site is the site where 2 molecules of CAP protein and 4 molecules of c-AMP in a complex binds. This binding of CAP-cAMP at the CAP site facilitates the binding of RNA polymerase to the promotor. RNA polymerase can't bind the promoter efficiently without the aid of CAP-cAMP complex
(CAP- catabolite activator protein, cAMP- cyclic AMP)
Promotor is the region where RNA polymerase binds for transcription of lac structural genes to take take place.
lac operator is the site between promoter and lac structural genes that interacts with the regulatory protein, repressor and controls the transcription of the operon.
lacZ- encodes β-galactosidase.
lacY - encodes Permease
lacA - encodes transacetylase
The lac operon genotype of the E.Coli in the question is- I+P+OCZ+CAP+
The structure of lac operon of genotype I+P+OCZ+CAP+ is-
lacI+ |
CAP site |
Promoter |
lac Oc |
lac Z+ |
Lac Y+ |
lacA+ |
This shows there is a mutation in the lac operator, lac Oc mutation. The lac Oc mutation leads to constitutive expression of the lac operon genes. This is due to base- pair alterations of the operator DNA sequence which doesn't let it bind to the repressor protein. Hence, the structural genes are constitutively expressed in case of lac Oc mutation both in the presence or absence of the repressor protein.
It is mentioned in the question, that E.Coli are grown on two different mediums - 1) a medium containing only glucose, and 2) a medium containing only lactose.
When E. Coli are grown on a medium containing only glucose, catabolite repression or glucose effect occurs. In this, the lac operon is expressed at only very low levels. This is because glucose causes the amount of cAMP in the cell to be reduced greatly. Hence, insufficient numbers of CAP- cAMP complexes are available to bind at the CAP site. As a result, RNA polymerase is not recruited properly to the lac promoter, can't bind efficiently at the promoter and the lac genes are not transcribed. This low level of transcription is unaffected by mutations in operator (lac Oc) or by the absence of repressor proteins.
When E.Coli are grown on a medium containing only lactose, then positive regulation of lac operon takes place. This is possible because in this case cAMP is present in sufficient numbers to bind CAP and form CAP-cAMP complexes which are able to bind at the CAP site efficiently. As a result CAP-cAMP complexes are able to recruit RNA polymerase at the lac promoter efficiently and hence transcription of structural genes is initiated.
So, it can be concluded that-
Results of Northern blot with a probe for β-galactosidase-
Image of Northern blot with a probe for β-galactosidase-
You plate colonies of E. coli with the lac operon genotype of I+P+OCZ+CAP+ on 1) a...
The lac operon in E. coli is a well-studied gene system, and β-galactosidase (β-gal) is the product of the lacZ gene. The diploid conditions represent the addition of a plasmid carrying different components of the lac operon. Determine if β-gal will be generated under the conditions. Assume that glucose is absent. A + in the genotype indicates a functioning gene, while a – indicates a loss-of-function allele. The OC is an operator mutant that cannot bind the lacI protein. Use...
Please solve all of them Lac Mutants 1-Copy 2 of 10 CAP laclCAP gene lacO lacP acolacZacY Carbon source in theLac operon p-galactosidaseLactose permease binding site me levels in levels in the cell polycistronic mRNA enzy levels in the cell Undetectable Low but detectable Low but deteteable Low but detectable medium the cell Undetectable membrane Glucose only Glucose and lactose Lactose on Another carbon source Undetectable Undetectable Undetectable Undetectable The table shows the results of experiments measuring expression of the...
Consider the following lac operon genotype: laci+P+OCZY+A+ In an E. coli strain with this genotype, what is the status of beta- galactosidase activity in the PRESENCE of lactose? O A. - OB. + c. Can't tell
26. The lac operon in E. coli consists of genes that code for enzymes necessary for the breakdown of lactose. When lactose is absent, the operon is inactive because a repressor protein binds to a specific site in the lac operon. When lactose is present, lactose molecules bind to the repressor protein, causing the repressor protein to dissociate from the binding site. In the absence of glucose (a preferred energy source for bacteria), the protein CAP binds to a regulatory...
Three different strains of E. coli carry a mutation in the lac operon and/or laci gene. The production of B-galactosidase (+ present or - absent) is measured when lactose is present and absent from the medium. Assume the mutations involve only 1, 0, or Z. A merodiploid is constructed for each of the three strains. The plasmid carries a wild type lac operon and lacl gene. The production of functional B-galactosidase (+ present or - absent) is measured when lactose...
4. (3) Suppose that you mate a lac+ Hfr strain with the genotype str S i+ o+ z+ y+ (that you grew in the absence of lactose) with a lac - F - strain with the genotype str R i- o+ z - y. You allow sufficient time for the transfer of the genes indicated, with the exception of str S , and plate the bacteria on minimal medium supplemented with arabinose and streptomycin but no lactose. You observe transient...
3. The CAP activator protein and the Lac repressor both control the Lac operon (see Figure 28-14). Fill out the table below with No expression, Low/Medium expression, or High expression to summarize when the Lac operon will be expressed in each of the three E. coli strains in the table. An example has been done for you. RNA polymerase- binding site (promoter) CAP binding site start site for RNA synthesis operator Lacz gene -80 -40 14080 nucleotide pairs Figure 08-14...
2. Suppose you have six strains of E. coli. One is wild type, and each of the other five has a single one of the following mutations: lacZ, lacY, laď·0; and lach. For each of these six strains, describe the phenotype you would observe using the following assays. Explain your answers. [Notes: (1) IPTG is a colorless synthetic molecule that acts as an inducer of lac operon expression but cannot serve as a carbon source for bacterial growth because it...
The genotypes of the lac operon of several haploid and partial diploid E. coli strains are given. For each genotype, indicate the status of B-galactosidase synthesis as either Yes or No. Assume that no glucose is present and cAMP is rich in the growth medium. • Oc is a mutant operator that cannot be bound by the wild type repressor protein. • Is is a mutant of repressor gene and cannot bind to operator Haploid Partial Diploid IOZY IOCZY ISOZY...
You are asked to develop a demonstration to show how the lac operon works. You decide to use X-gal and IPTG to determine if the enzyme ?-galactosidase is active. X-gal is a lactose analog that turns blue when metabolized by ?-galactosidase, but it does not induce the lac operon. IPTG is an inducer of the lac operon, but is not metabolized by ?-galactosidase. a. (2pts) Which of the following would you expect to bind to ?-galactosidase. Circle all that apply....