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2Homework Answers
1)
| for95% CI crtiical Z = | 1.960 | from excel:normsinv(0.975) |
| standard deviation σ= | 34.000 | |
| margin of error E = | 2 | |
| required n=(zσ/E)2 = | 1111 | Rounding up |
2)
94-1.645*6.46/sqrt(46) to 94 +1.645*6.46/sqrt(46)
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you are amazinggg !! thanks for the help im advance
At least one of the answers above is NOT correct. 14 of the questions remain unanswered. (1 point) Use the following information for all parts of this problem. On a particular golf course, a sample of 46 golfers have a mean golf score of 94. Suppose the population standard deviation for this course is 6.46. - Part 1: Using the formula a 90% confidence interval as presented in lecture, fill...
please tell me what to fill in therw ive tried & it keeps telling its wrong...
please tell me what to fill in therw ive tried & it keeps
telling its wrong
1 point) Use the following information for all parts of this problem. On a particular golf course, a sample of 46 golfers have a mean golf score of 94. Suppose the population standard deviation for this course is 6.46. Part 1: Using the formula a 90% confidence interval as presented in lecture, fill in the blanks with the appropriate values for this problem for...
(10 pts) Use the following information for all parts: On a particular golf course, a sample...
(10 pts) Use the following information for all parts:
On a particular golf course, a sample of 40 golfers have a mean
golf score of 79. Suppose the population standard deviation for
this course is 3.6605.
(a) Using the formula a 90% confidence interval as
presented in lecture, fill in the blanks with the appropriate
values for this problem for calculating the confidence interval
below. To enter
where x is any number, type sqrt(x). For example,
should be typed as...
thank you for helping me, i appreciate this so much, you are amazing !! Entered Answer...
thank you for helping me, i appreciate this so much, you are
amazing !!
Entered Answer Preview Result 3.2498 3.2498 correct 3.94623 3.94623 incorrect At least one of the answers above is NOT correct. (1 point) A random sample of 10 size AA batteries for toys yield a mean of 3.84 hours with standard deviation, 1.2 hours. (a) Find the critical value, r*, for a 99% confidence interval.rº 3.2498 (b) Find the margin of error for a 99% confidence interval....
Entered Answer Preview Result Message -2009.11, 2009.11 -2009.11, 2009.11 incorrect Your answer isn't a number (it...
Entered Answer Preview Result Message -2009.11, 2009.11 -2009.11, 2009.11 incorrect Your answer isn't a number (it looks like a list of numbers) 41686.9 41686.9 correct 45705.1 45705.1 correct At least one of the answers above is NOT correct. (1 point) Starting salaries of 95 college graduates who have taken a statistics course have a mean of $43,696. Suppose the distribution of this population is normal and has a standard deviation of $10,819. Using a 93% confidence level, find both of...
(1 point) Use the following information for all parts of this problem. On a particular golf...
(1 point) Use the following information for all parts of this problem. On a particular golf course, a sample of 44 golfers have a mean golf score of 83. Suppose the population standard deviation for this course is 4.72 Part 1: Part 2: Using the formula from part 1, find a 95% confidence interval for the mean golf score of all golfers. Round each answer to the nearest hundredth (2 decimal places) to
i appreciate all your help! thank you so much 1 2 At least one of the...
i appreciate all your help! thank you so much
1
2
At least one of the answers above is NOT correct. (1 point) How much money do winners go home with from the television quiz show Jeopardy? To determine an answer, a random sample of winners was drawn and the amount of money each won was recorded and listed below. Estimate with 94% confidence the mean winning's for all the show's players. 27451 32924 40287 31460 38597 33788 24733 32231...
(1 point) Use the following information for all parts of this problem. On a particular golf...
(1 point) Use the following information for all parts of this problem. On a particular golf course, a sample of 44 golfers have a mean golf score of 83. Suppose the population standard deviation for this course is 4.72. Part 1: Part 2: Using the formula from part 1, find a 95% confidence interval for the mean golf score of all golfers. Round each answer to the nearest hundredth (2 decimal places). 81.61 to 84.39 Part 3: Calculate the margin...
Question 1 (1 point) A customer wants to estimate the average delivery time of a pizza...
Question 1 (1 point) A customer wants to estimate the average delivery time of a pizza from the local pizza parlor. Over the course of a few months, the customer orders 29 pizzas and records the delivery times. The average delivery time is 23.69 with a standard deviation of 7.212. If the customer estimates the time using a 95% confidence interval, what is the margin of error? Question 1 options: 1) 0.7137 2) 2.2782 3) 2.7433 4) 1.3392 5) 2.739...
i appreciate all the help! thank you so much 1 2 Entered Answer Preview Result -0.05...
i appreciate all the help! thank you so much
1
2
Entered Answer Preview Result -0.05 -0.05 incorrect -1.9599 -1.9599 correct -3.0619 -3.0619 correct B B correct At least one of the answers above is NOT correct. (1 point) it is necessary for an automobile producer to estimate the number of miles per gallon achieved by its cars. Suppose that the sample mean for a random sample of 150 cars is 29.1 miles and assume the standard deviation is 2.4...
you are amazinggg !! thanks for the help im advance
At least one of the answers above is NOT correct. 14 of the questions remain unanswered. (1 point) Use the following information for all parts of this problem. On a particular golf course, a sample of 46 golfers have a mean golf score of 94. Suppose the population standard deviation for this course is 6.46. - Part 1: Using the formula a 90% confidence interval as presented in lecture, fill...
please tell me what to fill in therw ive tried & it keeps
telling its wrong
1 point) Use the following information for all parts of this problem. On a particular golf course, a sample of 46 golfers have a mean golf score of 94. Suppose the population standard deviation for this course is 6.46. Part 1: Using the formula a 90% confidence interval as presented in lecture, fill in the blanks with the appropriate values for this problem for...
(10 pts) Use the following information for all parts:
On a particular golf course, a sample of 40 golfers have a mean
golf score of 79. Suppose the population standard deviation for
this course is 3.6605.
(a) Using the formula a 90% confidence interval as
presented in lecture, fill in the blanks with the appropriate
values for this problem for calculating the confidence interval
below. To enter
where x is any number, type sqrt(x). For example,
should be typed as...
thank you for helping me, i appreciate this so much, you are
amazing !!
Entered Answer Preview Result 3.2498 3.2498 correct 3.94623 3.94623 incorrect At least one of the answers above is NOT correct. (1 point) A random sample of 10 size AA batteries for toys yield a mean of 3.84 hours with standard deviation, 1.2 hours. (a) Find the critical value, r*, for a 99% confidence interval.rº 3.2498 (b) Find the margin of error for a 99% confidence interval....
Entered Answer Preview Result Message -2009.11, 2009.11 -2009.11, 2009.11 incorrect Your answer isn't a number (it looks like a list of numbers) 41686.9 41686.9 correct 45705.1 45705.1 correct At least one of the answers above is NOT correct. (1 point) Starting salaries of 95 college graduates who have taken a statistics course have a mean of $43,696. Suppose the distribution of this population is normal and has a standard deviation of $10,819. Using a 93% confidence level, find both of...
(1 point) Use the following information for all parts of this problem. On a particular golf course, a sample of 44 golfers have a mean golf score of 83. Suppose the population standard deviation for this course is 4.72 Part 1: Part 2: Using the formula from part 1, find a 95% confidence interval for the mean golf score of all golfers. Round each answer to the nearest hundredth (2 decimal places) to
i appreciate all your help! thank you so much
1
2
At least one of the answers above is NOT correct. (1 point) How much money do winners go home with from the television quiz show Jeopardy? To determine an answer, a random sample of winners was drawn and the amount of money each won was recorded and listed below. Estimate with 94% confidence the mean winning's for all the show's players. 27451 32924 40287 31460 38597 33788 24733 32231...
(1 point) Use the following information for all parts of this problem. On a particular golf course, a sample of 44 golfers have a mean golf score of 83. Suppose the population standard deviation for this course is 4.72. Part 1: Part 2: Using the formula from part 1, find a 95% confidence interval for the mean golf score of all golfers. Round each answer to the nearest hundredth (2 decimal places). 81.61 to 84.39 Part 3: Calculate the margin...
i appreciate all the help! thank you so much
1
2
Entered Answer Preview Result -0.05 -0.05 incorrect -1.9599 -1.9599 correct -3.0619 -3.0619 correct B B correct At least one of the answers above is NOT correct. (1 point) it is necessary for an automobile producer to estimate the number of miles per gallon achieved by its cars. Suppose that the sample mean for a random sample of 150 cars is 29.1 miles and assume the standard deviation is 2.4...
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