Question

A random sample of 50 students is selected and it is found that the mean of daily internet usage is 70.8 minutes with standard deviation of 13.8 minutes. A hypothesis test was performed to determine whether the true mean usage, µ equal to 72.0 minutes or not. What is the p-value of the test?

Answer 1

H0: $\mu$ = 72

Ha: $\mu$ $\neq$ 72

Test statistics

t = (
T
- $\mu$ ) / ( S / sqrt(n) )

= ( 70.8 - 72) / (13.8 / sqrt(50) )

= -0.61

From T table.

With test statistics of 0.61 and df of 49,

two tailed p-value = 0.5447