Solution-
we have information that the survival rate of the operation is 80% (0.80)
p = 0.80
5 patient have this operation.
n = 5
Mean of binomial distribution is-
= n × p = 5 × 0.80 = 4
The Mean number of patient who survive this operation is-
4
The survival rate during a risky operation for patients with no other hope of survival is...
5 pts The survival rate during a risky operation for patients with no other hope of survival is 80%. If 5 patients have this operation. This event follows a binomial distribution What is the mean number patients who survive this operation?
The survival rate during a risky operation for patients with no other hope of survival i 80%. If 5 patients have this operation. This event follows a binomial distribution What is the standard deviation of patients who survive this operation?
The survival rate during a risky operation for patients with no other hope of survival is 81%. What is the probability that exactly four of the next five patients survive this operation? (Give your answer correct to three decimal places.)
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