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The survival rate during a risky operation for patients with no other hope of survival is 80%. If 5 patients have this operat
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Solution-

we have information that the survival rate of the operation is 80% (0.80)

p = 0.80

5 patient have this operation.

n = 5

Mean of binomial distribution is-

= n × p = 5 × 0.80 = 4

The Mean number of patient who survive this operation is-

4

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