The survival rate during a risky operation for patients with no other hope of survival is...

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The survival rate during a risky operation for patients with no other hope of survival is...

The survival rate during a risky operation for patients with no other hope of survival is 81%. What is the probability that exactly four of the next five patients survive this operation? (Give your answer correct to three decimal places.)

math Statistics-And-Probability

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Answer 1

Answer #1

Solution

Given that ,

p =81%= 0.81

q = 1 - p = 1 - 0.81 = 0.19

n = 5

Using binomial probability formula ,

P(X = x) = (n C x) * p x * (1 - p)n - x

P(X = 4) = (5 C 4) * 0.81 4 * (0.19)5- 4

probability =0.409

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Answer 2

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The survival rate during a risky operation for patients with no other hope of survival is...

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