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ne angular velocity of the disk is w= (5t+ 2) rad/s where t is in seconds. termine the magnitude of the normal component of a
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Answer #1

The angular velocity at the given time is;

\omega = 5t^2 + 2

\Rightarrow \omega = 5(0.5)^2 + 2

\Rightarrow \omega =3.25\;\;rad/s

NORMAL COMPONENT of acceleration is given as;

(a_A)_n = \omega^2 r_A

\Rightarrow (a_A)_n = (3.25)^2 (0.8)

\Rightarrow (a_A)_n =8.45\;\;m/s^2

\Rightarrow (a_A)_n =\mathbf{8.45}

...(Answer)

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