Solution :
Mean d=16.4
Standard deviation =Sd=14.183
Sample size n=10
Let 1 be the mean score after the test and
let 2 be the mean score before the test.
Hence, represents the improvement of score after taking the test.
Hence, the Null Hypothesis: H0: the difference between the scores after taking the test and before taking the test is equal to 15 marks.
Alternate Hypothesis:H1 : the difference between the scores after taking the test and before taking the test is more than 15 marks.
i.e.
H0 :
H1 :
Test statistic = (16.4-15)/(14. 183/sq(10)) =0.312
Degrees of freedom df= n-1=9
Significance level =0.01
P value = 0.3811
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