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Find the solution of 4?2?″+6?2?′+?=0,?>04x2y″+6x2y′+y=0,x>0 of the form ?1=??(1+?1?+?2?2+?3?3+⋯)y1=xr(1+c1x+c2x2+c3x3+⋯) Enter Need help getting last coefficient (1 point) Find the solution of 4x2y" + 6x2y + y = 0, x > 0 of the form yı = x" (1 + (1x + c2x² + c3x3 + ...) Enter r = 1/2 ci = -3/4 C2 = 27/64 = -405/1408
(1 point) Find the solution of xy" + 5xy' + (4 + 1x)y = 0, x > 0 of the form Yi = x n=0 where co = 1. Enter r = -2 Cn = - n= 1,2,3,...
(1 point) Find the solution of x2y" + 5xy + (4 + 3x)y = 0, x > 0 of the form Yi = x" Ž Cpx”, n=0 where co = : 1. Enter r = Cn = n = 1,2,3,...
(1 point) Find the solution of x²y" + 5xy' + (4 – 3x) y = 0, x > 0 of the form y=x" Wazek, k=0 where ao = 1. r = help (numbers) ak = , k=1,2,3,... help (formulas)
1 point) (a) Find the general solution to y" +7y'-0. Give your answer as y -.. . In your answer, use ci and c2 to denote arbitrary constants and x the independent variable. Enter ci as c1 and c as c2 help (equations) (b) Find the particular solution that satisfies y(0) 1 and y'(0)1 help (equations)
The answer above is NOT correct. (1 point) Find the general solution to y(4) – 8y"" + 15y" = 0. In your answer, use C1,C2,C3 and C4 to denote arbitrary constants and x the independent variable. Enter ci as c1, c2 as c2, etc. y=c1+xc1+c3e^(3x)+c4e^(5x) help (equations)
Need it fast !! 1. Graph the solution region for the following: 2x + y<3 1x – 2y -1
please help The general solution of the equation y4y 0 is y = ccos(2x)c2sin(2x) Find values of ci and c2 so that y(0) and y (0) 8 -3 C1 = C2= Plug these values into the general solution to obtain the unique solution y = The general solution of the equation y4y 0 is y = ccos(2x)c2sin(2x) Find values of ci and c2 so that y(0) and y (0) 8 -3 C1 = C2= Plug these values into the general...
=> (x² - 6x) y - y = 0 Find the singular point and ordinary point of this equation.
QUESTION 11 Find the solution of x' + 2x' +x=f(t), x(0)=1, x'(o=0, where f(t) = 1 if t< 2; and f(t) = 0 if t> 2.