Question

Find the solution of 4?2?″+6?2?′+?=0,?>04x2y″+6x2y′+y=0,x>0
of the form

?1=??(1+?1?+?2?2+?3?3+⋯)y1=xr(1+c1x+c2x2+c3x3+⋯)

Enter
(1 point) Find the solution of 4x2y + 6x2y + y = 0, x > 0 of the form yı = x (1 + (1x + c2x² + c3x3 + ...) Enter r = 1/2 ciNeed help getting last coefficient

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Answer #1

Please thumbs up for this solution...thanks..

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last coefficient = -45/256

3/2 3/2 3/1 1. ह ) + -- ) C24 4(0 Gmpall coelfiuk 39+ 3+Gco ISC t 27 1 99 64 1SC (3 + 3S 3 ISC 32 36 3 -45 256

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Find the solution of 4?2?″+6?2?′+?=0,?>04x2y″+6x2y′+y=0,x>0 of the form ?1=??(1+?1?+?2?2+?3?3+⋯)y1=xr(1+c1x+c2x2+c3x3+⋯) Enter Need help getting last coefficient (1...
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