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Find the speed of the basketball (in ft/s) when it leaves the shooters hand at point A. You may assume the shot passes throu

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Answer #1

The speed of the basket ball when it leaves the shooter's hand at point A is, Va = 36.69 ft/s

xot Vantt 11 Given : Vay sio o = 0.58a Va Vancoso = 0.867 Va uft = y 7ft = 40 x=30ft solution : time it is air i 2 x = Vaxt 3* Y = Yo + Vayt + 12 gt² () +46-32175 10 ft = 7ft +0.5vá 52 30 ft 2 0,367 Va 2 900 ft 10 ft = 7ft +17.3 ft - (16.69 ft/? 0.75

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