Question

Measurements of a shot recorded on a videotape during a basketball game are shown. The ball passed through the hoop even though it barely cleared the hand of player B who attempted to block it. Neglecting the size of the ball, determine the magnitude va of its initial velocity and the height h of the ball when it passes over player B. 30° A 10 ft 7 ft 25 ft

Answer 1

ACCORDING TO THE DATA AND THE DIAGRAM ARE GIVEN IN THE QUESTION,

Giren, g= = 32.2 ft/8. B С 330° A loft Ift 25ft 5 ft for horizontal we can woite, %=0ft 2B = 25ft X с 30 ft V = V(6530 for vertical Yo = oft = B Bt (10-7) ft = 3ft YB = (h-7) ft vý = vsin 30° Yc a = 32.2

Eq? fos horizontal motion, X = 40 + ( Vt 30 = O + V Cos 30ºt time ť 30 UCOS 30° + V Now equation for vertical motion Yc t +1 (ad) t² 0 + vsin 30"(t) + 16-ą) t? Yo 9 32.2 २ 32.2 2 3 euring Vsin 30 GO + ht (*BI) / 30 VCE30 VCOs30 32-2 3 99 z 17.32 900 102(0.75) 2 lez (32.2)(900) 2(0:75) (14.32) 22 = 1349.162 V = 3673 ft/s ! tns Initial velocity

Using initial velocity value we can write two equations, + Vrt 0 + (36.73 60530')}{4-7) = 0 + (36.73 $ingot) t= 0. 7868 +1(-32 Ho Xo Ye - Yo +(V.) + !ąť? 25 2.2) (+) २. h-7 = (36 73 sin30) (0.786) – 322 (0.786) ? 2 h = 11-487 ft Ans