Question

The figure below shows five resistors and two batteries connected in a circuit. What are the currents 11, 12, and 13? (Consider the following values: R1 = 1.10, R2 = 2.04, R3 = 3.08 , R4 = 4.160, R5 = 6.16 0. Due to the nature of this problem, do not use rounded intermediate values in your calculations-including answers submitted in WebAssign. Indicate the direction with the sign of your answer.) 11 = 12 = 13 = RS 12.0 V R2 9.00 V R4 R

Answer 1

here,

using KVL in the upper loop

(R3 + R5) * I1 + R2 * I3 = 12

(3.08 + 6.16) * I1 + 2.04 * I3 = 12 ......(1)

and

using KVL in the lower loop

(R4 + R1) * I2 - R2 * I3 = 9

(4.16 + 1.1) * I2 - 2.04 * I3 = 9 .......(2)

and

using KCL

I1 = I2 + I3 .......(3)

from (1),(2) and (3)

I1 = 1.36 A

I2 = 1.61 A

I3 = - 0.26 A